Question

PLEASE COMPLETE ALL WITH DETAILED WORK, NO EXPLANATIONS REQUIRED JUST STEP BY STEP WORK.

Chemical Equilibrium.Submit your answers and work as a PDF file into Canvas. Check that your responses are clear and legible. (1) (6 pts total) Consider the following two gas-phase equilibria in a sealed container at 1200 K (a) (2 pes) What is the mass-action expression and value of the equilibrium constant K for the following equilibrium at 1200 K? (b) (2 pts) What is the mass-action expression and value of the oquilibrium constant Ke for the following oquilibrium at 1200 K? (c) (2 pts) If, at equilibrium at 1200 K, the partial pressure of O: () is 0.200 atm and the partial pressure of N0le) is 0500 atm, which is the most abundand N containing gas species, N-O)NOor Nos) in the container? (2) (4 pts total) Sugpest four ways in which the equilibrium concentration of SO (g)can be increased in a closed container if the only chemical equilibrium is (3) (12 pts total) When coke, which we can assume to be only solid carbon, is burned in air at 900 K and 1.0 atm, Co(g) and Co:(g) are produced according to the equilibrium processes C(s) + ½Oj(g)--CO(g); (i) (ii) Ki)1.40x 10 Kii)-9.44 x 10 C(s)+0, (g)CO. (g) (a) (2 pts) Write down two other distinct equilabrium processes that are possible involving C(s),Olg CO(g) and COg) as reaction components. (Each process should contain just three of the four chemical species listed, and reverse reactions of (i) and (ii) are not allowed) (b) (4 pts) For each of the two equilibria written for part (a), write down the mass-action expressions for the (c) (2 pts) Using the equilibria written for part (a), write down the two reactions (one for each equilibrium (d) (4 pts) Using the equilibria in part (a), wrie down the rwo reactions (one for each equilibrium) that will p(CO:)- 5x 10 atm; equilibrium constants K and determine their numerical valucs at 900 K process) that will occur when the total pressure is raised to 2.0 atm occur when the following initial conditions are set (i) p(CO) = 5.00 atm; (i) p(CO)-3 x 10 atm, p(O2) = 0.500 atm. p(O)-0.300 atm. p(CO:)-3.00 atm;

Answer 1