Question

6:04 PM Wed Apr 22 5 TODO of ☺ + 0 The Beam is subjected to a distributed load, determine the shear force diagram and bending moment diagram Calculate the numerical values of the graphs. Express the maximum shear force and bending moment 20kN/m 10KN 3m om 4m

Answer 1

solution - EBD TO KN 1 20 kN/m m K-3-*-4- K- 6- EMA aos 10x3 + 20X6x10 - VeX 13 20 - Ve = 94,61 KN Vat ve = 10 + 2046 Efy zo o - VVA = 35.30 KN Shear & moment Equation at a from pt. A :- at x = o-3 Eat BMcx) 2 fy=0 > V(X) = VA (VXO) = 35.30kw t IM(X) = 35.38% o -0 EM207

at 2= 3-7 TOKN I SMO() VI096 Efy=0; V(X)= 35.30 - 10 Tvcx = 25. 38 KN EMEO -> M(x)= 35.38X – 10 (32-3) Ima) = 95.38% +30 — atx=7-13 :- to my SMEs) (( e-x z fy 10 → Val = 95.30 - 20(2-7) Next Soxt | VOQ = -20% + 165.38 EM=0} MCX) = 95,382 +30-20 (-7) M O )= 35,300+ 30 -10 (2-7)2

Shear force & Binding moment Diagram using above C Equation v1-3K-4- (KN) 35.38 KN 25,30 KN -94.62 KN 223,76 kN-M 207,66 106.14 from figure --- maximum shear force = 35.30 KN (tve ) = -94,62 KN (-ve) maxim Bending moment = 223.76 KN-M

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