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Section 114 © Chelsea nandale - CHM 112 - Summer 19 - BORING > Activities and Due Dates Section 11.4 200/400 Resources [ Give
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Answer #1

vapour pressure of pure benzene = P0 = 100.84 torr

mass of Biphenyl = w=(solute) = 13.9 grans

molar mass of Biphenyl = m= 154.21 gram/mole

mass of benzene = W= 25.1 grams(solvent)

molar mass of benzene = M = 78.11 gram/mole

vapour pressure of the solution = P =?

according to Raoults law

P0 - P / P0 = w/m x M/W

100.84 - P / 100.84 = 13.9/154.21 x 78.11/25,1

100.84 - P / 100.84 = 0.280

100.84 - P = 28.2352

P = 72.6 torr

vapour pressure of the solution = P = 72.6 torr.

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