vapour pressure of pure benzene = P0 = 100.84 torr
mass of Biphenyl = w=(solute) = 13.9 grans
molar mass of Biphenyl = m= 154.21 gram/mole
mass of benzene = W= 25.1 grams(solvent)
molar mass of benzene = M = 78.11 gram/mole
vapour pressure of the solution = P =?
according to Raoults law
P0 - P / P0 = w/m x M/W
100.84 - P / 100.84 = 13.9/154.21 x 78.11/25,1
100.84 - P / 100.84 = 0.280
100.84 - P = 28.2352
P = 72.6 torr
vapour pressure of the solution = P = 72.6 torr.
Section 114 © Chelsea nandale - CHM 112 - Summer 19 - BORING > Activities and...
HW 11 itivities and Due Dates HW 11 re: 62.3% Resources Biphenyl, CiH, is a nonvolatile, nonionizing solute that is soluble in benzene, C.H. At 25 °C, the vapor pressure of pure benzene is 100.84 Torr. What is the vapor pressure of a solution made from dissolving 16.2 g of biphenyl in 32.8 g of benzene? Psolutie