An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the
skater pulls in her arms, her moment of inertia decreases to 50.0 kg•m2. What is
the skater’s resulting angular velocity?
apply angular momentum conservation
Li = Lf
70*41 = 50 *w
w = 70*41/50 = 57.4 rpm
or 57.4 *2pi /60 = 6.01091394 rad/s
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An ice skater with moment of inertia 70.0 kg•m2 is spinning at 41.0 rpm. If the...
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