| sample mean 'x̄= | 15.800 |
| sample size n= | 78.00 |
| std deviation s= | 1.900 |
| std error ='sx=s/√n= | 0.2151 |
| for 95% CI; and 77 df, value of t= | 1.9910 | |
| margin of error E=t*std error = | 0.428 | |
| lower bound=sample mean-E = | 15.372 | |
| Upper bound=sample mean+E = | 16.228 | |
| from above 95% confidence interval for population mean =(15.4 <μ< 16.2) | ||
help! Karen wants to advertise how many chocolate chips are in each Big Chip cookie at...
Karen wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. She randomly selects a sample of 76 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 11.8 and a standard deviation of 3.8. What is the 90% confidence interval for the number of chocolate chips per cookie for Big Chip cookies? Enter your answers accurate to one decimal place (because the sample statistics are...
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1. Jose wants to advertise how many chocolate chips are in each Big Chip cookie at his bakery. He randomly selects a sample of 51 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 10.7 and a standard deviation of 2.6. What is the 90% confidence interval for the number of chocolate chips per cookie for Big Chip cookies? Assume the data is from a normally distributed population ________<M<_________ 2.In a...