Question

Two uniformly charges rods (each with a total charge Q 7.5 HC and length L. - 12.0 em) are arranged as shown below. Find the electric field at P if a -5.5 cm. s. .75

Answer 1

For this problem, we more so calculate electric field due so the nods of a point p at a din have x from one end of rod as the both rods are identical then they will produce same amount of electric field at point p. but the difference in that their direction in different and they will act at an angle 75 degree to each other how, let us calculate electric field due to the rod lying along x axis to find the electric field rod us filed on element length dx at a distance n from point p. so, charge on this elemental length dq = lambda dx where x being the change percent length and lambda = q/L now, electric field at point p due to dq in dE = 1/4 pi elelemtof_0 = dq/x^2 direction along positive x axis or, E_1 = 1/4 pi c_0 integral dq/x^2 x = a