Question

An unknown object weights 17.0 N in air. When the object is suspended by a light cord and totally immersed in water, the tension in the cord is 11.0 N. Find the object’s volume and density?

Answer 1

Weight of the object, IT Mg = 17 Ni Fb and density - mg. hed the volume of object is v of object is 8, of density water is 1000 kg/m3. So buyoant force, fo=vdq Tension, T= (mg-fred o Fb = Mg-T Now Tell N, So, v dg= Mg-T 17-11) V = m3 Mg-I lovox9.8 do V 3 m 6.12X107, - to find Now density of the object M VP fa M V 17N Im? s = 3834.5 17 g.v 9.8x6,12x109 kg/m3 so volume of the object is 6,12x109 m3 and the densi of the object is 12839.5 kg/m sity 3