calculate the pH of [OH-] = 5.6x10-3M

Question

Question

science chemistry

Answer 1

Answer #1

Ans. Method 1:

pOH = -log [OH^-] = -log (5.6 x 10^-3) = 2.25

Now,

pH + pOH = 14.00 - equation 1

or, pH = 14.00 – pOH = 14.00 – 2.25 = 11.749 = 11.75

Thus, pH = 11.75

Method 2: [H⁺] [OH^-] = 10^-14 - equation 2

Or, [H⁺] = 10^-14 / [OH^-] = 10^-14 / (5.6 x 10^-3) = 1.7857 x 10^-12

Now,

pH = -log [H⁺] = -log (1.7857 x 10^-12) = 11.748 = 11.75

Thus, pH = 11.75

Answer 2

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