Question

Ques The average number of miles driven on a full tank of gas in a certain model car before its low-fuel light comes on is 373. Assume this mileage normal distribution with a standard deviation of 36 miles. Complete parts a through d below. a. What is the probability that, before the low-fuel light comes on the car will travel less than 393 miles on the next tank of gas? (Round to four decimal places as needed.) b. What is the probability that, before the low-fuel light comes on, the car will travel more than 337 miles on the next tank of gas? (Round to four decimal places as needed.) c. What is the probability that, before the low-fuel light comes on, the car will travel between 330 and 350 miles on the next tank of gas? (Round to four decimal places as needed.) d. What is the probability that, before the low-fuel light comes on, the car will travel exactly 360 miles on the next tank of gas? (Round to four decimal places as needed.)

Answer 1

Mean=373, SD-36) de get X-up393! 0.5556 X-887 361 36 -1.00 Amsuzo) Date:) 4/5/2020 Mean=373, SD 36 1 @ P(xc 398) 2- (y-my sp = (319-973) - 36 ) 0:56 P(240.66) = 0.7183 0 P(x>831) - HP(X<337) 2= (x-M/S= (337–373) 636 Plzc-1.00) = 0.1587 P(X> 337)= 1 - 0,1587= 0,8413 © PC 8300XC 350) = P(x86) - PCX<230) PCX<330) = Plzc 3332) + Plze +119) 011170 PCX= 550) - plac 350-813 ) - plza 0,64)= 0.8611 PC 330 c X 350) = 0.861) - 0.1170= 0:144) It is not discocete dista i bution U-1907). That is why we do not get probability of exact values the P(x=360)=0 This is forte fall values of that has normal distonibution 36 36