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1. Simplify the following expression a. j22 = b. 2j? +3j* = C. (5j?) = d. j j = f. 3j(2j? –5j)= g. 6xjº +2yj“ + 4xj +5yje =

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233 by 4, t ind reminder step -0: Divide 133 ID 1270935 24014 4) 233 (58 20 33 2706 (34)59 - j O 270 step@: 5233 becomes eqrstep O: Enpand (5j) to oder onginal form . (5j) = 5x j = 125 j? step@: 4s know : we . put j%= -j = 125 (-j) 125j => -> 5i) =step0: Dinide power o j by 4t find neminder 4)3 (0 step O: 16 stepO -> = om-n step@: Ac 4-3 (d. 16 -> Ans stepC 3j(2j²-5i)= sStels ® : know: j2=-1 j3 = jj = -j and 6-1sj 6 (-5)- 15(-1) = 6j+15 3i(2j-5j) =-6j +15 %3D Ans ) 6xj+1 + 4xi + 5yj= step0:

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