Question

The figure shows a spherical hollow inside a lead sphere of radius R = 4.7 m; the surface of the hollow passes through the center of the sphere and touches the right side of the sphere. The mass of the sphere before hollowing was M = 268 kg. With what gravitational force does the hollowed-out lead sphere attract a small sphere of mass m = 40 kg that lies at a distance d = 11 m from the center of the lead sphere, on the straight line connecting the centers of the spheres and of the hollow? Number Units Use correct number of significant digits; the tolerance is +/-2% Click if you would like to show Work for this question: Open Show Work

Answer 1

M = 262Kg - те чок d = ilm - R=4.7m. Spherical hollow. and the center of mass of we can treat this system like a solid sphere of I mass M placed at origin and a Carity of moss -M placed at Its own Center 8 a R12 M -M18 mass of Cavity = ? use density Concept Cool Calze Xcom a min, that m, fm2 = mxo-MXR 8 R = So The distance Blw coom of M and m' is - r= dtr = 11t 01335 = 11:335m. TY F = GMm = 6.67 X10 X 268840 rz (11.33572 If=515681079 N Unit = N 5056 x 109 | Number =

M = 262Kg - те чок d = ilm - R=4.7m. Spherical hollow. and the center of mass of we can treat this system like a solid sphere of I mass M placed at origin and a Carity of moss -M placed at Its own Center 8 a R12 M -M18 mass of Cavity = ? use density Concept Cool Calze Xcom a min, that m, fm2 = mxo-MXR 8 R = So The distance Blw coom of M and m' is - r= dtr = 11t 01335 = 11:335m. TY F = GMm = 6.67 X10 X 268840 rz (11.33572 If=515681079 N Unit = N 5056 x 109 | Number =