Question

s 37 secs .00 O out of 100.00 How many mL of a 39% dextrose must you dilute to 121 mL to make a 6% solution? (MlV,-M,V2) Answer: 787 What is the pOH if the pH is 4.8? [H+1-10-pH pOH--log [OH-1 pH-14-pOH Answer: 9.2 Finish review
0 0
Add a comment Improve this question Transcribed image text
Answer #1

raiJ Mehdy:ゾ咇.xlo乂dauǐly 37x10x1 ะ 2.17 M /86 /8o 2.17 PH 4-42- 9.2

Add a comment
Know the answer?
Add Answer to:
s 37 secs .00 O out of 100.00 How many mL of a 39% dextrose must...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Determine how many mL of solution A(acetic acid-indicator solution) must be added to solution B (sodium...

    Determine how many mL of solution A(acetic acid-indicator solution) must be added to solution B (sodium acetate indicator solution) to obtain a buffer solution that is equimolar in acetate and acetic acid. You will need to refer to the Experimental Procedure, partcularly the section on calculations, to answer this question. Show all calculations. of an indicator 2. Determine how many ml of solution A (acetic acid-indicator solution) must be added to solution B sodium acetate-indicator solution) to obtain a buffer...

  • Titration: Acids and Bases 2. How can you determine which acid is diprotic? 3. using the...

    Titration: Acids and Bases 2. How can you determine which acid is diprotic? 3. using the answers to questions one and two, which acid is diprotic? 4. Which base has more hydroxide ions per molecule? Acid Volume Base Base Initial Volume (mL) Base Final Volume (mL) Volume of Base Used (mL) Acid: Base Ratio Acid 1 20 mL Base 1 50 mL 34.5 15.5 4:3 Acid 2 20 mL Base 1 Acid 1 20 mL Base 2 Acid 2 20...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT