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Can you please solve it fast?

Knowing that at the instant shown the rod attached at A has an angular velocity of 5 rad/s counterclockwise and an angular ac

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Siulon Apply the Law of sinep to the triangle ABP to determine the lengthy Ap and Bp , Angle APB= 180-25 110=450 Angle PBA =Angelcu valocker CAP (5 radio ) k WBPP (WBPjk Ingula Accelerations dap=r-zoredkeel) k a Bpz (dBpk velocla & pa up = Waptrp/Aand a relative acceleration Arol = ů (conlopt sint?) Consider a nod 3p as a rotating frame of selerance redion of point p onEqualing I componenty 0-56165 = 0.112336Bp tusiuzo Substitute ao 0.5616520-11231 bep20.11.2014 ) tusno 0.04083 u=-0.93971 heEquating a componenty -2.3265=-0.04080dpp- 0.41233 WBp+ucoplot5:0532 - O•0 4088dBp +ů wpzó = -0.41788 0 Equating I components

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