Question

Balance the following redox reaction in acidic solution. BrO3 + N2H4 - Br" + N2

Answer 1

Balance in acidic medium :- . Part-I Ro Br- + N2 Broz + N₂ 44 Part-I Balance Part - I. m) to Balance adding Br 03 - Br- oxygen atom, Three H2O molecules on the right hand side Rrez - - By- + 3 H2O (Both side no. of oxygen Balanced) (ii) Now we Balance Hydrogen atom, six Hydrogen ion added on the left hand side. BY Q + 6HO - BRO + 3 H20 1. (Both side noo of Hydrogen balanced) (1) Now We Balance electron , six electoon added - on the left hand side. Broj + 614@ +600 - By© + 3 H2O (Both side charger Balanced) - o Balance Equation for Rieduction part :( Part-I). Equation – Balance part-I i Nå H4 - N₂ (i) Balance Hydrogen atom; Four Hydrogen ion added on the ringht hand side. My H4 N₂ + 4H0

(ii) Now Balance electron, four electron added on right hand side N2 H4 - N2 + 4H® +420 a Equation - Balance Equation for oxidation Post ( Port-I) Last step; în Both Equation we have to remove election, 4x [B10@ + 6H@ +6e@ — Br® + 3H20 ] 6x [NZ H4 N2 + 4H® + 4C@ ] non 4 B70,0 + 24 HⓇ + 240 — 4 Bro + 12 H2O 6N₂144 - GN₂ + 24 HO +2400 ---- ....@ Adding ③ and 6 [4B103Ⓡ + 6N2 H4 4B70 + 6N2 + 12420] This is the balance equation in acidic medium. 2 Brog + 3 N₂ ta - 2 Bro + 3N2 + 6H₂O