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help pls 3

Problem 3. The truss supports a 100 kN load at J. The horizontal members are each Im in length Use the method of joints to de
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.K et KhI look a) using methool oq joints at joint I Fy=0 E sin 45 = 100 · - = 1002 KN EFx EO Fay sin 45= Für Fits = 100k FHT® using method of sections consider Right side of section 0-0 100 KN moment about joint fem 50, 100x2-FX120 FDE 200KM. + Tens

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