Question

5) The total mass of a crucible and some copper(II) sulfate hydrate in the cruible was 34.567 g. The crucible (with copper (II) sulfate hydrate in it was heated at 110 °C for 30 minutes. And the total mass decreased to 33.125 g. How many grams of mass was lost during heating? B) 1.44g A) 1.4420g C) 18 D) 1.4g E) 1.442g 6) Assuming that all are measured quantities, complete the following operation and express the result in the correct number of figures. 0.213/(0.02390 / 12.30) A) 1.10 x 102 B) 0.72 C) 1.1 x 103 D) 0.725 E) 1.10 x 103 * 7) Assuming that all are measured quantities, complete the following operation and express the result in the correct number of figures. 0.213/(0.02390-2.315) A) -0.0930 B) -0.930 C) 6.60 D) 0.0930 E) -6.60 8) Assuming that all are measured quantities, complete the following operation and express the result in the correct number of figures. (0.213-0.02390)/2.315 A) 8.17 B) 0.0817 C) 0.817 D) 0.203 E) 0.2027 9) What is the Fahrenheit equivalent of a temperature of 525.0°C.? A) 1230°F B) 9450F C) 9450°F D) 578°F E) 977.0°F

Answer 1

Rules for significant figure calculation :- In case of addition, subtraction it is rounded to lowest number In case of multiplication / division it is sounded to lowest number of significant figures 8 decimal places.

Ans :- Ano -5) Mass lost 34.5679 – 33.1259 1.4429 E) 1.4429 Ans-6) 0.213/(0-02390/12-30) 0-213/ 0.001943 (Rounding to 3 significant 1.10 x 102 Aru:- A) 1.10 x 102 Ano- 6-7) 0.213/(0.02390-2-315) 0.213/(-2-291) = -0.09297 (Rounding to 3 significant 109.64 figures) figures) --0.0930 :: Ano :- A) -0-0930 Ano-8) (0-213-0.02390)/2-315 0-189/2-315 0.0817 :: Ano:- B) 0.0817 Ano-9) Jemperature - 525.0°C Temperature in Jahrenheit =$9x 525.0°C +321 °F = 977° F .. Ans :- E) 977.0°F

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