here option B is correct
yes because the calculated F value is greater then the critical value
Anova: Single Factor SUMMARY Count Av Variance Sum 165.000000000 27.500000000 8.300000000 174.000000000 29.000000000 2.000000000 155.000000000 25.833333333...
Anova: Single Factor SUMMARY Groups Count Sum Average Variance Control No Exercise 15 1061 70.7333333 107.638095 Group 2 Cardio 15 948 63.2 63.1714286 Group 3 Cardio + Lifting 15 936 62.4 72.5428571 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 634.177778 2 317.088889 3.90900908 0.02774085 3.21994229 Within Groups 3406.93333 42 81.1174603 Total 4041.11111 44 Based on whether or not you rejected or accepted your null hypothesis, what can you state about the resting heart rates...
Question Completion Status QUESTION 4 Anova: Single Factor SUMMARY Groups Count Sum Average Variance A 4 108 27 32.66666667 B 4 96 24 13.33333333 4 120 30 56 ANOVA Source of Variation SS df F crit MS P-value F Treatments 72 36 1.058823529 0.386396621 4.256494729 Error 306 9 34 Total 378 11 Based on the Results above of Single Factor ANOVA: the MSTR O 36 O 378 O 72 O 34 Click Save and Submit to save and submit. Chick...
In a test of weight loss programs, 120 subjects were divided such that 40 subjects followed each of 3 diets. Each was weighed a year after starting the diet and the results are in the ANOVA table below. Use a 0.05 significance level to test the claim that the mean weight loss is the same for the different diets. Source of Variation SS df MS F P-value Fcrit Between Groups 91.990 2 45.99487 1.3743 0.257070 3.073763 Within Groups 3915.738 117...
An accounting professor wants to know if students perform the same on the departmental final exam irrespective of the accounting section they attend. She randomly selects the exam scores of 39 students from four sections. A portion of the output from conducting a one-way ANOVA test is shown in the accompanying table. Assume exam scores are normally distributed. a. Find the missing values in the ANoVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS to 2...
HWCh13 ANOVA Saved 4 Exercise 13-67 Algo 59 points At a gymnastics meet, three judges evaluate the balance beam performances of five gymnasts. The judges use a scale of 1 to 10, where 10 is a perfect score. A statistician wants to examine the objectivity and consistency of the judges. Assume scores are normally distributed. (You may find it useful to reference the q table.) eBook Gymnast 1 Gymnast 2 Gymnast 3 Gymnast 4 Gymnast 5 Judge 1 9.4 9.3...
Anova: Single Factor SUMMARY Groups Count Average Variance A 30 4.967 5.344 B 30 4.567 3.220 C 30 7.267 7.375 D 30 6.500 7.638 E 30 9.400 12.248 Compare Group E to Group A What is the t-value for this test? What is the P-value for this test? What is the confidence interval for mean difference in this test? Keeping in mind that the Margin of Error is the difference from the mean difference to either value above, what is...
A consumer advocate examines whether the longevity of car batteries (measured in years) is affected by the brand name (factor A) and whether or not the car is kept in a garage (factor B). Interaction is suspected. The results are shown in the accompanying table. Brand Name of Battery Kept in Garage? A B C Yes 6, 8, 8 5, 5, 5 7, 9, 10 No 7, 6, 6 5, 5, 5 7, 7, 7 a-1. Construct an ANOVA table....
newconnect.mheducation.com Student Homa Chapter 13 Quiz A Gat Hamework Halp With Chagg Study C Salved: An accounting prafassor wants o k Chapter 13 Quiz A Help Save & ExitSubmit An accounting professor wants to know if students perform the same on the departmental final exam irrespective of the accounting section they attend. She randomly selects the exam scores of 51 students from six sections. A portion of the output from conductinga one-way ANOVA test is shown in the accompanying table....
T test statistic
Anova: Single Factor SUMMARY Groups Count CAR1 CAR2 CAR3 CAR4 SumAverage Variance 178.9 19.87778 9.309444 11119.4 10.85455 10.15873 11241.1 21.91818 13.06164 14.49 7.894333 9 10 144.9 ANOVA Source of Varid Ss MS P-value F crit Between ( 815.10793 271.7026 26.61437 2.39E-09 2.8587916 Within Gr 377.7282 37 10.20887 Total 1192.836 40 Conduct a test of hypothesis that the mean mileage of makes 2 and 3 do not differ. Use the method for single means when σ is not...
Section 1 Section 2 Section 3 A statistics instructor wonders whether significant differences exist in her students' final exam scores in her three different sections. She randomly selects the scores from 10 students in each section. A portion of the data is shown in the accompanying table. Assume exam scores are normally distributed. (You may find it useful to reference the F table.) Click here for the Excel Data File Section 1 Section 2 Section 3 64 85 69 70...