Question

12. Humerus bones from the same species of animals tend to have approximately the same length-to-width ratios. Forty-nine (49) fossils of humerus bones were unearthed at an 2/1 archeological site where species A is believed to have inhabited. The sample mean ratio is 9.254, and the sample standard deviation is 1.201. Suppose you want to find out whether the unearthed bones are from species A. It is known that the mean length-to-width ratio of species A is 9.0. The specific statement that you want to verify is that the population mean length-to-width ratio of humerus bones unearthed at the site is different from 9.0. Answer the following questions:

(1) Build the null and alternative hypotheses given that this is the statement you tend to promote.

(2) Conduct a hypothesis testing to draw a statistical conclusion regarding whether to reject the null hypothesis or not at the significance level (α) of 5%. Report the P-value of the test.

(3) Based on the hypothesis testing you performed in part (2), can you conclude practically that the population mean length-to-width ratio of the humerus bones unearthed at the site is the same as 9.0 (or that the unearthed bones are from species A)? Explain why

Answer 1

please like me my solution sir/madam

Sol Given data Sample mean n = 9.254 population mean N 9,0 Standard Deviation & 21.201 Sample size n=49 1. Null Hapotheis Holt M = 9.0 2. Altea native Hypothesis (Ho: M#9.0 3. Level of significance d ;0.05 4. The teet statistic is a=4-M olsn Z. 9.254- -1.480 - 1. 201/549 calculated z=1.480 The tabulated a for 51 level of signifi- cance is 1.96. The calculated a value <tabulated 2 value. So we accept the well Hypothers Ho. and we conclude that there is no difference between them, P-value Plz>1.480) = P(z> 1480 ) =0.5-P(Z >1.480) -0.5-0.4306 P = 0.0694