Question

If you could, a picture of the correct graph would be nice. Also the calculated slope is 0.0256, according to the book.

13.115 A silver concentration cell is constructed with the electrolyte at both electrodes being initially 0.10 M AgNO(aq) at 25°C. The electrolyte at one electrode is diluted by a factor of 10 five times and the cell potential measured each time. (a) Plot the potential of this cell on a graph as a function of InſAg 'Janode (b) Calculate the value of the slope of the line. To what term in the Nernst equation does this value correspond? Is the value you determined from the plot consistent with the value you would calculate from the values in that term? If not consistent, calculate your percentage error. (c) What is the value of the y-intercept? To what term in the Nernst equation does this value correspond?

Answer 1

hF Solution . In concentration cell, electrode having high concentration form Cathode electrode while electrode having low concertention form ahall; Ecle = h i en Ecell = -27 lns) where 01362 C at cathode ca at anode ha hof electrons ehvolved I 1 in reaction T = absolute temperature R = gas constant f = fazaday constant; at 256 , Ecell = – 0.0592 log () . for Ag concertachion cell nah Ags) Agian te # initially bom Ecat = - Dresyr sogle) electrode has olim Agt .. Ecell = -ooosg2 bey (1) Ecell = 0 Ics Scanned with

ho times dilation ie [Anodi] = 0.10 M = 0.0m because Anode will have lower concentration side, lol Ecall = -0.0592 Borg (0-01) Ecell = -0.0592 X (-1) =.0.0592 V 1 # again to time dilution; [Anode] =ool 20.00/m. E Ecell = -drosg2 x dog (0.001) Ecell = -0.0592X (-2) = 0;1184 v. * again to times dibution, (Anode] = 0.ool = 0.0001 m. Ecell = -0.0591 X ley (0.000) Eeell = -0.0592 X (-3) = 0.1776 v # Again 10 times dilation , [Anode] = oroool 20.000lm Ecell = 20.0592 xlog (a.coop) Ecell = -0.0592 X Cryj = 0.2368 V # Again to time dilution, [Anode] = 0.00001 Ecell = -0.0592 x log (0.000001) Scannee reilph= -0.0592 X (-5) = 12.960 V ZXX 00001 0.00uoolm 5 CamScanner

0.35+ y 0.15+ Ecell Seria fx-00257°x-0.0592, RL 0.1 + In(anode) -0.15 03 Scanned with isän 0 Re © Ô L M

Table : Ecell I [Anode [Anodel ] In Canode] -2.3026. 0.1 M 8.0592 oool M o.1184 -4.6052 -6.9078 .9.2103 w11.5129 13.8155 0.001 M 0.000/ m 0.0000 m 0.00000) M 01776 0.2368 02960 l Ecell = -RT lu (anode]" ...nf . [agthode] Ecell = In Canode)- en [cathode] / inf Eceller en Canada) + Chi en centrale] y = mx + slope =m= .RT - hf. intercept on y-axes = i= at ln [cathodo] .hr Scanned with CamScanner

From graph; y = -0.0257 x – 0-0592 ,RP=1 Sloje = -0.0257 intercept = -0.0592 be Theoretical valine of slope = - RT = -8 314 3 2 1 X 298k -pol g65ooc IX = -0.02567 = -0.0257 Theoretical value of intexcept = + Rp On [cathode] = +8.3145/kthal X 298k xln (0:1) 1X 96500€ = +8314x29% TX 36560 X 144.5026) =-00591 1 # The values obtained from graph are consistent with the Values calculated; - Slope is componding to - 27 ... and intercept is corresponding to +RT en enthocle] NF hf Scanned with CamScanner