Answer is B 31. A substance has a density of 1,800 kg/m in the liquid state....
#1 The molar enthalpy of vaporization of Substance B is 28.9 kJ/mol, and its normal boiling point is 80.7 °C. What is the vapor pressure of Substance B at 22.1 °C. Respond with the vapor pressure in torr #2 Substance D has the following properties: ΔHvap = 18.9 kJ/mol ΔHfus = 3.5 kJ/mol Tb = 58.4 °C Tm = -39.8 °C Specific Heat (solid) = 3.8 J/g·°C Specific Heat (liquid) = 2.7 J/g·°C Specific Heat (gas) = 0.9 J/g·°C Calculate...
Question 2 (1 point) Substance A has a higher normal boiling point than substance B. Therefore, substance A has a higher latent heat of vaporization, and a plot of the natural ogarithm of vapor pressure vs. the inverse of temperature for substance A will have a steeper slope than that of substance B. True False Question 3 (1 point) The term -A/T in the Antoine equation is dimensionless. Perform a unit analysis on this term What are the units for...
The vapor pressure of a liquid is the pressure exerted by its vapor when the liquid and vapor states are in equilibrium. The relationship between vapor pressure P and temperature T is expressed by the Clausius-Clapeyron equation. lnP2P1=ΔHvapR(1T1−1T2) where P1 and P2 are the vapor pressures at the absolute temperatures T1 and T2, respectively, ΔHvap is the heat of vaporization of the substance in joules per mole, and R is the ideal gas constant, which is equal to 8.3145 J/(mol⋅K)....
Carbon disulfide, CS2 , is a volatile, flammable liquid. It has a vapor pressure of 400.0 mmHg at 28.0˚C and a boiling point of 46.5˚C. a) What is the heat of vaporization of this substance in kJ/mol? b) At which pressure would CS2 have a boiling point of 75˚C?
A liquid substance has a specific heat of 1592 J/(kg * K) and density 1159 kg/m^3. How much Energy is required to warm 2.59 mL of this liquid from 7.09 deg F to 194 deg F, in Joules?
Pleases help me thanks.
5 kg of liquid water at 100°C was converted to steam at 100°C by boiling at standard atmospheric pressure, in the arrangement of the figure below. The volume of the water changed from an initial value of 0.005 mº as a liquid to 8.355 mº as steam. Latent heat of vaporization for water Lv = 2256 kJ/kg. Standard atmospheric pressure is 1 atm or 1.01 x 109 Pa. Loaded Piston Steam Insulation Insulation Liquid water Thermal...
4. Liquid ammonia has a vapor pressure of 109 mm Hg at-66°C and a heat of vaporization of 2.46 x 10 J/mol. a) Estimate the normal boiling point of ammonia. b) Estimate the ratio of the vapor pressure at -66°C to that at -45°C
4. Liquid ammonia has a vapor pressure of 109 mm Hg at-66°C and a heat of vaporization of 2.46 x 10 J/mol. a) Estimate the normal boiling point of ammonia. b) Estimate the ratio of the...
1. a. The enthalpy of vaporization of liquid mercury is 59.11 kJ/mol. What quantity of energy as heat is required to vaporize 0.240 mL of mercury at 357 °C, its normal boiling point? The density of mercury is 13.6 g/mL. Energy = ____ kJ b. Determine ethanol’s normal boiling point by slowly changing the temperature to the point where the vapor pressure equals 760 mmHg. What is this temperature? °C
A liquid has a vapor pressure of 150 torr at 60ºC. The molar heat of vaporization for this substance is 40.8 kJ/mol. Determine the normal boiling point of this liquid. {ln(P1/P2 ) = ∆Hvap/R(T1-T2/T1T2) = ∆Hvap/R(1/T2 - 1/T1); ln P = 2.303 log P}
Please just answer Part 2
The vaporization of 1 mole of liquid water (the system) at 100.9°C, 100 atm, s endothermic. H0HOg) Assume that at exactly 100.0°C and 1.00 atm total pressure, 1.00 mole of liquid water and 1.00 mole of water vapor occupy 18.80 mL and 30.62 L, respectively 5th attempt d See Periodic Table See Hint (0.5 point) Part 1 Calculate the work done on or by the system when 1.85 mol of liquid H20 vaporizes. 5736.23319:J (0.5...