Question

Write a PYTHON program that does the following: (instructions in the picture) Please use a 3.5 version; You can use this website to write the code and then share the link here; because if you write the code and post here, it will have a problem with the indentations

https://repl.it/languages/python3

Answer 1

Here is the code for you:

#!/usr/bin/python
def numberSpelling(number):
num2words = {1: 'One', 2: 'Two', 3: 'Three', 4: 'Four', 5: 'Five', \
6: 'Six', 7: 'Seven', 8: 'Eight', 9: 'Nine', 10: 'Ten', \
11: 'Eleven', 12: 'Twelve', 13: 'Thirteen', 14: 'Fourteen', \
15: 'Fifteen', 16: 'Sixteen', 17: 'Seventeen', 18: 'Eighteen', \
19: 'Nineteen', 20: 'Twenty', 30: 'Thirty', 40: 'Forty', \
50: 'Fifty', 60: 'Sixty', 70: 'Seventy', 80: 'Eighty', \
90: 'Ninety', 0: 'Zero'}
output = '';
if number >= 100:
return num2words[number / 100] + ' hundred ' + numberSpelling(number % 100)
elif number >= 20:
return num2words[number / 10 * 10] + ' ' + numberSpelling(number % 10)
elif number >= 1:
return num2words[number]
else:
return 'zero'
  
  
def charCount(number):
return len(numberSpelling(number)) - numberSpelling(number).count(' ')
number = input('Enter an integer between 0 - 1000: ')
if(number < 0 or number > 1000):
print 'Invalid range.'
else:
while(charCount(number) != 4):
print numberSpelling(number), ' is ', charCount(number), '.'
number = charCount(number)
print numberSpelling(number), ' is ', charCount(number), '.'
print 'four is magic.'