Let p denotes the true proportion of asthma among Boston children.

Case Study 2: Suppose we know that the prevalence of asthma among American children is 11%....
There was a 5-year study of asthma among children in the state of RI. Children were followed and assessed for new asthma cases every year. At the beginning of the study 17out of 2,400 children already had had asthma. At the first early assessment, 15 more kids had developed asthma. At the second yearly assessment, 20 more kids had developed asthma. At the third assessment, 34 more kids had developed asthma. At the fourth yearly assessment, 25 more kids had...
A case-control study of the relationship between asthma and a history of pertussis vaccination among children (2-3 years old) was conducted in one community. Although overall participation was good, not all parents of cases and controls could be interviewed. A difference in the proportion interviewed based on case/control status (asthma/no asthma) and based on day care enrollment was identified by the investigators. Only 63% of control parents with a child enrolled in day care could be interviewed, versus 82% of...
In a study to find the proportion of children with asthma in a certain population we desire a 95% confidence interval with standard error no more than 0.05. Without any prior knowledge of the proportion. what should be our minimum sample size? O 80 o 92 096 100
2. In another vaccination study, the incidence of chicken pox among non-vaccinated children, younger than 12, was found to be 200/1,000 and the incidence among the vaccinated was 101,000. From another source we know that 30% of the total population (under 12 years of age) was not vaccinated, calculate the following for the given data: (a) The incidence of chicken pox attributable to non-vaccination of the total (under 12) (2 pts) (b) The proportion of the risk of chicken pox...
A case-control study was conducted to determine the association between smoking and coronary heart disease. The investigators found an odds ratio of 1.8 for coronary heart disease among subjects who smoked compared to those who didn’t smoke. The 95% confidence interval for this odds ratio was 0.8-4.3 and the P-value was 0.10. 1. State in words your interpretation of the odds ratio. 2. State in words your interpretation of the 95% confidence interval. 3. State in words your interpretation of...
Suppose you are interested in investigating the factors that affect the prevalence of tuberculosis among intravenous drug users. In a group of 97 individuals who admit to sharing needles, 24.7% had a positive tuberculin skin test result; among 161 drug users who deny sharing needles, 17.4% had a positive test result [15]. (a) Assuming that the population proportions of positive skin test results are in fact equal, estimate their common value p. (b) Test the null hypothesis that the proportions...
Is college worth it? Among a simple random sample of 338 American adults who do not have a four-year college degree and are not currently enrolled in school, 156 said they decided not to go to college because they could not afford school. 1. Calculate a 95% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context. Round to 4 decimal places. (, ) 2....
Is college worth it? Among a simple random sample of 350 American adults who do not have a four-year college degree and are not currently enrolled in school, 168 said they decided not to go to college because they could not afford school. 1. Calculate a 95% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context. Round to 4 decimal places. ( , ) 2....
Is college worth it? Among a simple random sample of 342 American adults who do not have a four-year college degree and are not currently enrolled in school, 158 said they decided not to go to college because they could not afford school. 1. Calculate a 95% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it, and interpret the interval in context. Round to 4 decimal places. ( , ) 2....
2. Suppose a study followed 1000 women aged 25-45 (when the study began) over 6 years and found that 50 acquired bacteriuria. a) Find a 95% confidence interval for the expected number of bacteriuria cases per 1000 women within 6 years. b) Find a 95% confidence interval for the incidence of bacteriuria per person-year. c) What is a 95% confidence interval for the incidence of bacteriuria per 100 person- years. 3. A study looked at the subgroup of 50-to 55-year-old...