Question

Brz H3C CH3 light or heat product

give the mechanism to explain the formation of this product. indicate the flow of electrons, show all intermediates, charges, and unpaired electrons

Answer 1

so, the formation of the product occurs via a radical mechanism

CH H3C CH3 CH H3C Br CH H2C CH3 H2C H3C CH Br Нас ње heat - 2 HBr CH 31 2 H2C CH3 CH2

The first step involves the Br₂ homolytic bond breaking by the light to give the two bromine radicals. The bromine radical forms a new bond using the electrons of the double bond in the alkene, generating a new radical centered in C. This radical rapidly enconteurs a new alkene molecule to react to give the 8 carbon compound. Then the termination of the radical chain by the collapse of Br radical and the molecule generates the dibromated compound. This structure is completely alyphatic so, to get the unsaturations we need to dehydrohalogenate by means of heat. In this case a concerted path is proposed for the elimination of HBr to get the alkene funtion.

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