Question

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y=0,y=cos(8x),x=π/16,x=0 about the axis y=−6

Answer 1

X y=-6 X y=0 X y = cos Br X X x = 0.196349540849

0.6 dr=cos8x -0-2

only area A given in first figure is bounded by given 4 lines

now you need to rotate it about y=-6

you can see around this line outer circle has radius 6+cos8x

and inner circle has radius 6

roatating this will have the area as difference

I ni 6+ Con on with repect to y=-6 dharan? difference of Area = . (6+ Cor 8.)? 262 = a (12+ Conon ) Cor&n = 122 Coobnte open Volure with thickness dariza Copbut a losbn) dn. & varies from 0 to 1/16 s come on du El It Coolen du (122 com ba ta con 8n) in = "127 Süs BA + * (** Siaks) J2 , Sinlóm 810 + 32 = 39 + 2 = 510208144