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Consider the structure in Figure 3. We will study the forces in the bars of this structure for various a. Develop the equatio
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Fc Los as c Finan 1m VE=2N FC = IN Ae sino Be osin ( 4 ) Cos 30 = BA 2 IBA = 1.732 m AD = DBABA DB = = 2 - 1.732 12:0. 268 mmoment about E. (Ro*1) - (1X0.288*1) - (2x2).(x los 45°) =0 R - 6,268 -4 - 070% so Road.97N JC Right ward] Rear 4.268w C Loft

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