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8. An adjustable positive linear voltage regulator (LM317) circuit with: R1 = 5600, R2 = 10ko, lADJ = 50uA and VREF = 1.25V S
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Answer #1

In 3 2 yout LM317 R1 -Cl To.iuf Vinh z СТ Vout Ra 10uF RT Vout = Vref & ( [+ + [adj RI R2 -6 560 + 50x108560, 560 Vout = 1125

Summary

There is adjustable resistor R2 present to adjust the value of current

From output voltage expression , Vout calculated

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