What is the molar flow rate (in lb-mole/min) of ethylene glycol (C2H6O2) given a volumetric flow rate of 55.0 ft3/min? Ethylene has an SG of 1.113.
volumetric flow rate of C2H6O2 = 55.0 ft3/min
Density of C2H6O2 = specific gravity x density of water
= 1.113 x 62.3
= 69.3399 lbm/ft3
Mass flow rate = density x volumetric flow rate
= 69.3399 lbm/ft3 x 55.0 ft3/min
= 3813.6945 lbm/min
Molar flow rate = mass flow rate / molecular weight
= (3813.6945 lbm/min) / (62.07 lbm/lbmol)
= 61.44 lbmole/min
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