Question

Please answer all parts of questions (20 to 26)

20: Make use of the following information for calculating the electron Affinity of C AH = -216 kJ A H2 249 kJ AH3 = + 240 kJ A H4 ? A H5 786 kJ A Ho-411 kJ 1: 2Na 2: ½ Na(g 3: Cl2() 4: Cl eg) 5: Na () Cl 6: Nas 2Nas ½ Na () 2Ck Deposition Energy Ionisation Energy Atomization Energy Electron affinity Lattice Energy Standard Enthalpy of Formation +½ e (g) NaCl NaCl 1/2Cl2(g) 21: Select the strongest and longest bond in the following group. C-C, O=O, N2 : Also rank them in order of increasing bond length and bond strength 22; rank the following in order of increasing electronegativity: Ba, Na, C, Cl, 23: Arrange the following bonds in order of increasing ionic character or bond polarity . S-O, B-CI, N-Br, K-I 24: The H-N-H bond angle in the NH3 molecule is and molecular geometry of Phosphorous penta-iodide are 25: The electron-domain geon and ctiv 26: Find electron-domain and molecular geometry bond angle, of the following mole cules: AB2E and AB3E

Answer 1

munity The Born Haber Cycle This is according to stoicion Al menotnom and the opposite reaction was t. must be eúdos e endo the rume = 120 kg Na(s) - Nalg), ang= +226 kJ = 108*5 á 01,(9) - a (), Aha +240 kJ Aneja -411 KJ Ang = 2*249 KJ , Nalg) e nälg. 52786 SHE = ? . celg) te utg). 49 QKJ Nace cate on from the Born haber apce, AMP - AHS + aMa tahs +AME +4+2 +498 + 4 HE – 786 OT-411 - 108 + 120 Or, the = -35) KJ Electron affinity of Chlorine. si Charneli 21, ce (single bond) - sp3 - 254. 5. Churata 0=0 / Double Bond) - Sp? _ 33.37. 3 clonado wen Triple Bond) ssp -50%. more s character when the hybridization hav in turn the át is more bound and Hightly bonds are shorter. i Stompost Bond as honest Band - Ng C-C.

order of Bond length NEN 050 4c-c. (In accordance with hybridization) Order of Bond Strength: c-c 50=0LNEN As when the mutiplicity of the bond innaes, the bond become more strong in native)