Question

The following table shows the approximate numbers of school goers in the United States (residents who attended some educational institution) in 1998, broken down by age group. Age 3-6.97-12.9 13-16.9 17-22.9 23-26. 927-42.9 Population (millions) 24 14 10 16 Use the rounded midpoints of the given measurement classes to compute the probability P distribution of the age X of a school goer. (Round probabilities to four decimal places.) Age 5 10 20 25 35 P(X = x) Compute the expected value of X, E(X). (Round your answer to one decimal place.) E(X) = What information does the expected value give about residents enrolled in schools? (Round your answer to one decimal place.) In 1998, --Select-- - was years old. ---Select--- Submit Answer the average age of a school goer each school goer

Answer 1

from the given data, the following table shows the approxinate numbers of school goers in the United States residents who attend some educational institutions in 1998, broken down by age group. 3-619 + 12.4 13-16.4 17-22.9 population (millions) L24 23-969 27-42.9 can be Total population = 73 The mid points of each Calculated by using the formula I lower limit of measurement class given below. upper limit et each class - Mid point = I each class I probability of each class Round the value to the nearest integer can be calculates as follows. P(x) = population of each class - Total population frequency distribution for x can be Constructed as selative follows. X P(x:x) 5 0.13 10 0.32 15 0.22 20 0.19 25 0.04 35 0.082

The expected value of a written E(x) 8 u, is M = E(X) 1 = {xx P (X=2) f(x) = (5x0.13) +10*0.32) + (15*0.22) + (90x0.19 ) + (25x o.ou) +(35 x 0.08) = 0.65 + 3.2 + 3.3+3.8 +1 +2.8 EX) = 14.75 a. . the The avera average age of a school goer in the United states in 1998 was 14.75 Note: If it is you. really helpful to you then like it. Thank