Question

For the state of stress shown in figure (a=55 degrees), determine (a) The normal and shear stress acting along the oblique fa

State of stress The state of stress shown corresponds to Ox= -10.32 (MPa),gy= 14.74 (MPa) and Txy= 21.384 * (MPa)

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compo Bompa Jeord gompa Q = - 80 MPa oomla S exy = gompa at oblique klone 2=550 nomal stress no = Story = -80-60 Bury copad +Date -(-80+60 sinloo t go woll0° - 10 sm 110.+ 90 cablloo Io = -21,384 mpg] ( state of stress, at oblique blone moa. =?!.384mба с алу , 5-(до с4 - онлаја за 1 -70 + 90.55 6 - 70 — 90. Ss 19, -50 55 тva) са - - По +90 ss L = rooss med 0 0 = -17° ng =Page No. Date. 48.17 Ky=80 mimor Philocibaſplane hence a major principal plane principal planes are 0 = 48.17°, 138-17° (minaPage No. Date. Tmax = -(Gry canro + Cry Coxzo - --do-Go) đi (34 ) + No co (Rx37) 1:104282 + 89.49 Temax = 90.55 mpg / 90.55 S

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