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How many grams of 3.85% (w/w) solution of KOH in water is needed to neutralize completely...

How many grams of 3.85% (w/w) solution of KOH in water is needed to neutralize completely the acid in 13.8 mL of 0.335 M H2SO4?

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Balanced chemical equation: H2SO, (aq) + 2KOH (aq) > K2SO, (aą) + 2H20(0) mass ofH,G04-73.66%(0.8543 g)-0.6293 g No of moles

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