Question

Using C++

e) Write a single statement to set the element of t in row O and column 1 to zero. f) Write a nested for loop to set each element of t to one. g) Write code to total the elements of third column of t. h) Write nested for loop to read values from screen and store it in the array t. i) Write nested for loop to find and display the lowest element of t.

Answer 1

(e) t[0][1]=0;

(f) for(int i=0;i<rows;i++){ /* correct the name of size of row*/

for(int j=0;j<cols;j++){   /* correct the name of size of column*/

t[i][j]=1;

}

}

(g) int total=0;

for(int i=0;i<rows;i++){ /* correct the name of size of row*/

total+=t[i][3];

}

(h)

for(int i=0;i<rows;i++){ /* correct the name of size of row*/

for(int j=0;j<cols;j++){   /* correct the name of size of column*/

cin>>t[i][j];

}

}

(i) int min=t[0];

for(int i=0;i<rows;i++){ /* correct the name of size of row*/

for(int j=0;j<cols;j++){   /* correct the name of size of column*/

if(min>t[i][j])

min=t[i][j];;

}

}

cout<<min;