Question

How many bricks are contained in a chimney in the shape of a frustum whose height is 18.3 m, whose outer diameters are 1.2
m and 2.4 m, respectively, and whose inner diameters are 1 m and 2.2m, respectively. There are 530 bricks to a cubic mm of chimney.

Answer 1

1.am Inner diameter of lower base im od = 1 = 0.5m Innu clia. of oppu base = 2.2m de = 2.2 = 1.1m & heigh, h 18.3 m oo Voli of inne frustum g V = VIT (+1,883 V = 1J (-25 + -55 + 1:21) 18.5 0.6m ar - J (2.01)6.1) - 12.26151 m3 Now 8 = 0.6m and r = 1.2m, h= 18.3m es Vol of outer frostom, Vzo f ( x + 8; &' + Y3*) = £1 (0.36 +0.72 + 1.44 let's -|(2-52) 6-1 = 15.372 37 m3 . Required Volv- & -V, 15.372JT – 12.261 JT ) m? = 3.111 m3 ice : 1 m - 10 mm :. V: 3.11 xlo? Il mm - 3111 xlo J mm? - 3111 x 22 x 100 9777.43 x 100 mm 9717 x 100 mm I No. of bricks in 1 mm = 530 * No. of bricks in required Vol - 9777 X 530 x 10 = 5181810 X 10 bricks