Question

OB-5 cm OB-10 cm RT) + expi-B 2 3 266 / 50 Rotational quantum number J Figure 2.4 The Boltzmann populations of the rotational energy levels of Fig. 2.2. The diagram has been drawn taking values of B-5 and 10 cm and T - 300 K in Eq. (2.18). Rotational quantum number. J Figure 2.7 The total relative populations, including degeneracy, of the rotational energy levels of a diatomic molecule. The diagram has been drawn for the same conditions as Fig. 24 Maximum population: ) = KT1 2hcB 2

Answer 1

= 500 m 3 = T = 5 cm 300k J 1.38x10-23 x 300 \$*6.63x10-34 x3x108 x 500) = 10.020814 x 10+3) "2 - 0.5 = 4.56 -0.5 sa 4.06 B = Tocmt = 1000 mt 5= = - 0.5 1 10.407) #12 3.83 -0.5 2.73 cs Scanned with Scanned with CamScanner 123

B= scmt = soo my T = 16ook so . i 1.38x10-23 x 1600 - 0.5 2x6.63X10534 * 3x108x500 10.53% - 0.5 10.036 JE 10 CS Scanned with CamScanner
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