Question

The figure below shows two long, parallel wires in cross-section, and the currents they carry are directed out of the page. The left wire carries a current of I, = 2.86 A, and the right carries a current of I = 3.25 A. The two wires are a distance d = 20.0 cm apart. Point P is the same distance d above the right wire. Assume the +xr-direction is to the right, and the +y-direction is upward. I2 (a) What are the magnitude (in T) and direction (in degrees) of the net magnetic field due to the two wires at a point midway between the wires? Measure the angle counterclockwise from the positive x-axis, with the mid point at the origin of the coordinate system. (Ignore the magnetic field due to the Earth.) magnitude 7.8e-7 T direction 270 counterclockwise from the +x-axis (b) What are the magnitude (in T) and direction (in degrees) of the net magnetic field due to the two wires at a point P? Measure the angle counterclockwise from the positive x-axis, with point P at the origin of the coordinate system. (Ignore the magnetic field due to the Earth.) magnitude 3.98 From the location of point P with respect to I, what is the direction of the magnetic field due to I,? From this, vwhat are its x- and y components? What are the x- and y-components of the magnetic field due to I? What are the components of the net field, and what is its magnitude? T 159.7X direction From your calculation of the magnitude, what are the x- and y-compone trigonometry to determine the angle with respect to the horizontal. Remember that the angle being asked for is with respect to the positive x- of the net etic field at point P? Use the components and axis. counterclockwise from the +x-axis

Answer 1

Find the magnetic field due to each of the long current carrying wire along coordinate axes in vector form and add them using vector method to find the magnitude and direction of the resultant field as shown below

zar zid r= 2d b) 0 = 45° B = Byt B2 = no Ft (- cosoê + sinom) – 1012 î ceva - -4.68X10-6 î + 1.43x10-6 h 1B1 = JE 4: 68X10-6)* +(4:43X20-92 = 4.89x10-61 1.43x 10-6 4.68X10-6 Os 17° derechon = 180 -0 = 1637° TY tano = ! ¿ 71.43x10-6 X 4.68X106

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