Question

For the motor in Problems motor what is the slip at the pullout torque? What is the pullout torque of this

Answer 1

Y = 20su, y-Connected, f= 60Hz. poles pa4, slip 320.05 Pcose a low, Prech = 25000 R, 20:21, x, = X2 20.411, Re = 0.121 1 XM = 150 Ns = yes to a 120x60 z 1800 rpm. Zeq= Ritjx, + R + jxz) jxm Rhes tj x2 +jXm. 70-2430:41 + ( obs tj0:41) jis 0.12 + 0.41 tj 15 20.2630.4170 2.22 +30.745. Zeq = (2-68/25:51) @ Line Current I, el 2268/2551 2 =(14.30-23.58 )4. © State Copper loces > 3 LYR, = 3(44.7) kora 2082 S n = 1203. 378 W.

. Pin a VE VL I, Cosp = 13X208X 44.7excosas:51 Pt 2 14.86 kW. ] © Airgap powes Pag = Pin- stator copperloss Pose Panga 14:56X10?–1203-318–180 Pag = 13-176kw. ] (d) Convested Mechanical power fcon E Page C1–5)= 13-176X10% (1-0.05) Pcon = 12:518 kW] @ Enduced torque Tind = Sconto 6. Motor Speed dra Ns (-s) = 1800 (2005) Nr = 1710 rpm. wre 2tNr 21x1710 Twr = 179 rad/see 60 60 Du 12:518X10 X60 , 70 Num. Qax 1710 :) Tind ? to N-m.

Pont = fcon - Pmech. = 12:518X103_250 Pout = 12.268kw . ! * Load torque Tia Pont xbo- T - 12.268X102x60 20x1710 TL = 68:54N-mi X100 ② overall efficiency of Port x100 = 12:268x10^x100 14.56X103 7284.25%