Question

Write a C program which takes 5 numbers from the user. Write a switch case to...

Write a C program which takes 5 numbers from the user. Write a switch case to find out
how many numbers are even

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Answer #1

#include<stdio.h>
void main()
{
int a[5],i,count_even=0,count_odd=0;
printf("\n\nEnter any five numbers: ");
for(i=0;i<5;i++)
{
scanf("%d",&a[i]); // reading five numbers from the keyboard
}
for(i=0;i<5;i++)
{
switch(a[i]%2) // logic begins ere
{
case 0: // case matches when switch variable remainder is 0
   count_even++;
   break;
case 1: // case matches when switch variable remainder is 1
   count_odd++;
}
}
printf("Number of even numbers in the given list of numbers are %d",count_even);
printf("\nNumber of odd numbers in the given list of numbers are %d",count_odd);
}

Screenshots:

DOS | EOS 1 DOSBox 0.74, Cpu speed: max 100% cycles, Frameskip 0, Program: TC File Edit Search Run Compile Debug Project Opti

printf(Number of even numbers in the given list of numbers are zd,count_ev printf(\nNumber of odd numbers in the given li

Output:

28 DOSBox 0.74, Cpu speed: max 100% cycles, Frameskip 0, Program: TC - X Enter any five numbers: 5 10 15 20 25 Number of even

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