Question

An electron has an uncertainty in its position of 603pm .

What is the uncertainty in its velocity?
Express your answer with the appropriate units.

Answer 1

$\Delta$ p $\Delta$ x= h/4 $\pi$

m $\Delta$ v $\Delta$ x = h/4 $\pi$

$\Delta$ v = h/4 $\pi$ * m $\Delta$ x

h=6.63 *10^-34 m² Kg sec^-1   mass of electron (m) = 9.1*10^-31 kg   $\Delta$ x = 603pm = 603 *10^-12 m

$\Delta$ v = h/4 $\pi$ * m $\Delta$ x

      = 6.63 *10^-34 m² Kg sec^-1 / 4 * 3.14 * 9.1*10^-31 kg * 603*10^-12 m

      = 9.62 *10⁴ msec^-1