Question

Question 3: For the manometer-inverted manometer shown below, if all fluids are at 20°C and Ps - PA= 140 kPa, determine the height H in centimeters. Given the SG of mercury is 13.6. ogh Meriam red oil, SG=0.827 18 cm Water Mercury 35 cm 140 gg hw + 89 hm + gg hme leonia.) (rw) + egli sw)( (2 ) 9.9.1 .18)

Answer 1

Don't forget to change given lengths in "meter" and in equation all the units must be in SI Units. And follow step by step procedure. Good luck.

& Meriam AT ✓ Red oil x (Datums Line) Gravity Quer Given Change length in im poil 0.827 specific to water » 1 Ly Mercury = 13.6 S.G. 7 Peiquid twater I liquid side of a x water meruum water twater as 1000 Kg/m3 fig- Inverted Manometer foil » 827 kg/m3 mercury = 13600 Kg/m3 Po - PA » 140 kPa = 140000 N/m2 sol Pressure below x-x in left limb APA - 1000 x 9.81XH -827% 9.81 X 0.18 Pressure below x-x in right limb opp - 13600 x 9.81 x (0:53+H) {0:35+018+424 - -> 0.53+H] Equating the two pressure we get PA-1000X9-81x4 -827x9.81x018 = PA-13600 x 9.81X60-53PM) PRAPA = 133416 *10.53 +H) – 9810H - 1460.3166 → 140000 begiven 140000 = 70710.48 +133416 –98109H - 1460.3166 140000 69250. 1634 + 1236064 H>) 140 000 -69250.1634 123606 → 0.5723 m In 57.23 cm