Question

Write a program with a loop and indexed addressing that calculates the sum of all the gaps

between successive array elements. The array elements are doublewords, sequenced in nonde-

creasing order. So, for example, the array {0, 2, 5, 9, 10} has gaps of 2, 3, 4, and 1, whose sum

equals 10.

Answer 1

#include<iostream>
using namespace std;
int sumOfGaps(int arr[],int size){
int sum=0;
for(int i=0;i<size-1;i++)
// finding the difference between 2 elements and adding to sum
sum=sum+(abs(arr[i]-arr[i+1]));
return sum;
}
int main(){
int arr[]={0, 2, 5, 9, 10};
cout<<"Sum of gaps : "<<sumOfGaps(arr,5);
return 0;
}

1 #include<iostream» 2 using namespace std; 3 int sumOfGaps (int arr[],int size){ 4. int sum-0; for(int i-0;i<size-1;i++) /finding the difference between 2 elements and adding to sum 6 sum-sum+(abs (arri-arr[i+1])); return sum; 10 int main()A int arr[]-, 2, 5, 9, 10j; cout<<"Sum of gaps"<<sumOfGaps (arr,5); 12 13 14 return 0 Sum of gaps 10 . . Program finished with exit code 0 Press ENTER to exit console