Question

A bar is uniformly compressed by an axial force P 40 kN applied throurhard end plate (see figures. The bar consists of a circular steel core surrounded by brass and copper tubes. The steel core has diameter 30 mm, the brass tube has outer diameter 45 mm, and the copper tube has outer diameter 60 mm. The corresponding moduli of elasticity are = 210 GPa = 100 GPa, and E= 120 GPa. Calculate the compressive stresses and in the steel, brass, and copper, respectively, due to the force P. P-40 KN Copper tube Brass tube Steelcore

Answer 1

solution for the given problem is given below,

Given P = 40 kn Es = 210 Gla E = 100 apa Ę= 120 Gla do= 30mm do = 45 mm de - 60 mm

Total load = load taken by 3 rods P= P + Pote and strain in all 3 20dh is equal. Ps e L 68-45) 120x10? π (30) x 210x10 20100 காம் grande comes to > or otro - s = 1.6800 and esale 40,000 P + Vas Pop + > 40,000 2P + P 26(1:68) + 1.6 1.68 1.68 40,000 4.36 Ps 1.68 es = 15412.84 w

Ps= 1.6896 1.68 = 15412.85 1.68 Po=9174.310 P = Pb => [P6= 15412.84N

ctress in steel sod, os Ps I (302 = 15412.85 (20) Jos = 21.80 meal stress in brass tube rond, Ţ (55²-307) - 9175.31 (530) Too = 10.38mpa se = e = 15412.85 Ť 60-45) 7 (60355) Toc = 12.45 Meal stress in copper tube,

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