Question

Assuming that the array upc declared below has already been filled with MAX_LENGTH values, write a function that will ask to input an integer from the keyboard and perform a sequential search of the array for the input integer. If the input integer is found, print the index of the matching value in the array. Otherwise, print "Not found". Include declarations for all variables that you use.

            const int MAX_LENGTH = 25;

            int upc[MAX_LENGTH];

Please write in C++

Answer 1

This problem asks to write a function using c++ programming language. Code is commented properly. In case if you find any difficulties let me know in comment section.

HOPE YOU LIKE THE SOLUTION!!!!!

Function implementation:

void sequential_search(){
int search_ele; // variable to store search element
int n=sizeof(upc)/sizeof(upc[0]); // calculates the size of the array.
cout<<"Enter the search element: ";
cin>>search_ele;
cout<<search_ele<<endl;
// loop iterates over the array and compare each element with the search element and if match is found it prints its index.
for(int i=0;i<n;i++){
if(search_ele==upc[i]){
cout<<"Element found"<<" and index of element is "<<i<<endl;
return;
}
}
// if search element is not found then it prints the message "Not found".
cout<<"Not Found"<<endl;
}

Full program implementation:

#include <iostream>
using namespace std;
const int MAX_LENGTH=25;
int upc[MAX_LENGTH];
void sequential_search(){
int search_ele; // variable to store search element
int n=sizeof(upc)/sizeof(upc[0]); // calculates the size of the array.
cout<<"Enter the search element: ";
cin>>search_ele;
cout<<search_ele<<endl;
/* loop iterates over the array and compare each element with the searchelement and if match is found it prints its index. */
for(int i=0;i<n;i++){
if(search_ele==upc[i]){
cout<<"Element found"<<" and index of element is "<<i<<endl;
return;
}
}
// if search element is not found then it prints the message "Not found".
cout<<"Not Found"<<endl;
}
int main()
{
cout<<"Enter the number of values you want to enter: "<<endl;
int n;
cin>>n; // asks user for the size of array.
cout<<n<<endl;
cout<<"Enter "<<n<<" values"<<endl;
for(int i=0;i<n;i++){
cin>>upc[i];
cout<<upc[i]<<" ";
}
cout<<endl;
sequential_search(); // function call
return 0;
}

Code screenshot:

} نها 1 2 #include <iostream> 3 using namespace std; 4 const int MAX_LENGTH=25; 5 int upc [MAX_LENGTH]; 6- void sequential_search() { 7 int search_ele; // variable to store search element 8 int n=sizeof(upc)/sizeof(upc[0]); // calculates the size of the array. 9 cout<<"Enter the search element: "; 10 cin>>search_ele; 11 cout<<search_ele<<endl; 12 /* loop iterates over the array and compare each element with the searchelement and if match is found it prints its index. */ 13 for(int i=0;i<n;i++) { 14. if(search_ele==upc[i]) { 15 cout<<"Element found"<<" and index of element is "<<i<<endl; 16 return; 17 18 19 // if search element is not found then it prints the message "Not found". 20 cout<<"Not Found"<<endl; 21 } 22 int main() 23- { 24 cout<<"Enter the number of values you want to enter: "<<endl; 25 int n; 26 cin>>n; // asks user for the size of array. 27 cout<<n<<endl; 28 cout<<"Enter "<<n<<" values"<<endl; 29 for(int i=0;i<n;i++){ 30 cin>>upc[i]; 31 cout<<upc[i]<<" "; 32 33 cout<<endl; 34 sequential_search(); // function call 35 return 0; 36 } }

Output screenshot:

Sg++ -o main.cpp 5 1 2 3 4 5 4 Smain Enter the number of values you want to enter: 5 Enter 5 values 1 2 3 4 5 Enter the search element: 4 Element found and index of element is 3