Question

An aircraft flies at an airspeed of 280 mph with a rate of climb of 3500 ft/min through a vertical stationary cold front. The instruments on board the aircraft show that the air temperature drops at a rate of 1.2 oF/min. What is the rate of change of the air temperature (oF/mile) with respect to the horizontal difference through the cold front seen by an observer on the ground?

Answer 1

3500ft pin=3500X0.0113636 mph = 39.7726 mph o Ve = 2somph Given :- Rate of air temperature drop through Vesetical cold front = 1.2 Fmin si = 12 x60 oFh - s ť = 72 °F/M Now, considese Vector So AB for every mile of Horizontal difference corresponding Vettical Difference. ay= 39.7726 Y = 0.1420 280 Now air - distance @T)y temperature drop worot- vertical = s ť = 72 °F/h = 1.81 V 39.7726 mph ... so Rate of Change of air temperature with Seespect to horizontal difference etme = @T), xoy = 1.81 x 0.1420 = 0.257 °F) mile