Question

help

ents: Show your steps. Answers without adequate work will receive no credits. 1. (15 pts) Two point charges are located on the x axis as follows: charge - 4.80 nC at X -0.600 m, and charge g = + 3.60 nC at the origin. What is the net force (x, y components) exerted by these two charges on a third charge 43 - 5.00 nC located at x - 0.400 m?

Answer 1

-06 of oil x as [ 22 q3 Given that a, is a poput charge and q, = -4.80ne and is located at a distance of - 0:600 m from origin ou x-axis and other point charge is a = + 3.60 nc located at orighe. And another point charge is q = 5ione located at 0:400m from origin Now, we have to fud the force ou q due to q and qz Now, we will calculate this force by Coulomb's law which states the electic force is directly propitional to the magnitude of charged and inversely proportional to square of distance between them. f2 9,9₂ and t = ax 10" Nm²/ c2 - lurto Чт, 42 So, now force owq, due to q, & F3 = 9,23 Watt & 13 Now rug = 0.4-(-0.6) = 1.0m dia -4.80 nC X 5.0 nCam 109 (1)2 ---

- -4. 8ox lo-9 x 5.0x to 9 x9x109 And F1s = -216X10-9 N force ow.qz due toq, is 7232 9293 . 3.bone X 5ione xaxo" 10.432 Catorzo = 3.60 xl0 9x5.0 X10 X 4x109 . 0.16 = 10 12:5X 109. Now, the net force ou az is givens by Fret 2 Fiat F23 = -216 X10-9 + 1012.5X109 Inet = 79 6.5 8109 = 7.965 X164 N