Question

use python Write function letter2number() that takes as input a letter grade (A, B, C, D, F, possibly with a - or +) and returns the corresponding number grade. The numeric values for A, B, C, D, and F are 4, 3, 2, 1, 0. A + increases the number grade value by 0.3 and a - decreases it by 0.3.

>>> letter2number('A-') 3.7 >>> letter2number('B+') 3.3 >>> letter2number('D') 1.0

Answer 1

def letter2number(s):
    if s == 'A':
        return 4.0
    elif s == 'A-':
        return 3.7
    elif s == 'B+':
        return 3.3
    elif s == 'B':
        return 3.0
    elif s == 'B-':
        return 2.7
    elif s == 'C+':
        return 2.3
    elif s == 'C':
        return 2.0
    elif s == 'C-':
        return 1.7
    elif s == 'D+':
        return 1.3
    elif s == 'D':
        return 1.0
    else:
        return 0.0


# Testing the function here. ignore/remove the code below if not required
print(letter2number('A-'))
print(letter2number('B+'))
print(letter2number('D'))

3.7 3.3 1.0 Process finished with exit code 0