Question

يقوم الانتقال إلى السؤال آخر بحفظ هذا الرد السؤال 1 Determine:- (V1 Voy the BJT amplifier with a=0.988 shown in Figure (1). 55957 4.4668 3,0957 None Figure 1).pdf يقوم الانتقال إلى السوال آخر بحفظ هذا الرد :

Answer 1

DC analysis of the given BIT X = 0.988 Circuit with IZ 44.742 Corresponding 'ß' value is = 0988 ß = x = 0.98 VERT Jie la 1-0.988 |ß= 82.37 E 6. 8kr I or 3. VEB = 0.7 volts let. -6V - 6.8K 1g - VEB 20 -6.7 = 6-8k IE = -b.tm = If - ff = -0.985mA Ic = ß Tea 82-3 (-0.995m) =-0.973m 10H ße 83.3 (Icl=0.973m A just current flow in opposite direction - Ic - 0.973M = 38.92ms Im = 25m L 7 - B - m 82.3 k 38.92 = 2.1145kr AC analysis :- Too .bp &5kr Vo E6. 8kr 85002 I + is (1+B)

Apply KVL :- Vin - 500 I - 6.8k ( at ib (1+B)) = 0 1 + i (1+B) 6.8K - Vin = 500 1 + 6.86 -raia no 6.8K (It ib (1+B)) = 0 ib (a + 6.8k (176)] = - 618 KI is [2.1145k + 83-3(6-8k)] =- 6-8k I a. - 568.55k ip = -83.61 lb - 6.8K vin e (500+ 6.8K) 1 + (566.44K) i from eq ② → vien = 7.3k (-88.61)ůb + 16 (566.44C) vin at 610.353k ib+ 566.44K26) rin = – 43.913K ib = is a -vin - ③ 43.913K 43.93 Vo = - (4.7k 11 5k) is ß = -12.42K) (vin) (82.3) Vin = VS Vo = 199.38k vin Tvo = VL] Vo = 4.5405 vin ve a 4.5405/v/v 43.913K