When 1.8 x 10-3 mol of Zn is added to 300 mL of 1.5 M NH3,...

Question

Question

When 1.8 x 10-3 mol of Zn is added to 300 mL of 1.5 M NH3, [Zn2+] = ___ M when the system reaches equilibrium. For [Zn(NH3)4]2+, Kf = 2.9 × 10^9.

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Answer 1

Answer #1

Concentrati on of Zn* - 0.300L Initial (M) 0.006 Change (M) Equilibrium (M): 0.006-x1.5-4 Formati on constant, K, 2.9×109= (0

Answer 2

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