Question

Answers I've tried and have been wrong:

A convex lens (f = 13.9.cm) is placed 10.0 cm in front of a plane mirror. A matchstick is placed x = 29.3.cm in front of the lens, as shown in the figure. Convex Plane mirror lens -10.0 cm (a) If you look through the lens toward the mirror, where will you see the image of the matchstick relative to the lens? (Include the sign of each answer. Enter a negative value if the image forms to the right of the lens.) X cm (b) What is the magnification of the image? xx (c) Describe the image. (Select all that apply.) real virtual upright right of the lens inverted left of the lens

a) 6.54, 6.45, -6.45

b)-1.91, -.9

Please help, I cannot figure this one out.

Answer 1

(a)

use thin lens equation

1/di = 1/f - 1/x

1/di = 1/13.9 - 1/29.3

di = 26.446 cm

image distance from mirror = 16.446 cm

this becomes object distance at 16.446 - 10 = 6.446

so,

now object is to the right of lens, so object distance is negative

so,

1/13.9 = -1/6.446 + 1/di

di = 4.4037 cm

---------------------------------------------

(b)

magnification

m = ( 26.446 / 29.3) ( 4.4037 / - 6.446)

m = - 0.6166

----------------------------

(c) image is real, inverted

------------------------------------

(c)