Question

F y rbutions umcons and then compare them are there mobile Com Click the icon to vow the requency debbons Cotininingimi) Smokers Nonsmokers Exposed to make Smokers Frequency 100199 300399 400499 500 - Type nepers or decimas Do not round) Compare the distribution the Print Done ce? DA The two distributions tercantly Nonsmokers exposed to mother have a very high or a very w el of whisk onnte between 100 and 300 ml of con B. The two distributions cany The other com parto be much higher form s exposed to make than for nonsmokers C. The two distributions after s cany The peak of the distruton of concerto che form a oromo posto D. The two distrutos do modernoanty The peak of measution of cone is not incantly rent for smokers for nomokors exposed to smoke

Answer 1

The relative frequency percentages are computed as follows:

Percentage of smokers = Frequency of smokers - X 100 Frequency of smokers + Frequency of non-smokers Percentage of non-smokers = Frequency of non-smokers Frequency of smokers + Frequency of non-smokers era X 100

The completed relative frequency table is thus given below:

Continine (ng/ml)	Smokers	Nonsmokers exposed to smoke
0-99	23.63%	76.36%
100-199	85.71%	14.28%
200-299	94.73%	5.26%
300-399	50%	50%
400-499	71.42%	28.57%
500-599	0%	100%

Now, most smokers have 200-299 ng/ml continine while most nonsmokers exposed to smoke have 0-99 ng/ml of continine. Hence, the answer is given as follows:

ANSWER: (C) The two distributions differ significantly. The peak of the distribution of continine appears to be much higher for smokers than for nonsmokers exposed to smoke.