given
m = 92 kg
v = 0.875 m/s
l = 0.65 m
k = 0.354
F = 282 N
a. on the rough surface
net force = F - kN
N = mg
hence
Fnet = F - kmg = 282 - 0.354*92*9.81 = -37.49208 N ( opposite to the direction of motion of the cart)
b. work done on crate while it is on rough surface = W
W = F*l = 282*0.65 = 183.3 J
c. final speed = u
from conservation of energy
-37.49208*0.65 = 0.5*92(u^2 - 0.875^2)
u = 0.48 m/s
(b) How does the anewer change it the coefficient of kinetic tiction is Is p.1307 (use...
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